Why dont this work!

[Petrol Head]

1 HP per hour =half a lb of fuel per hour

Take the RPM times it by the C.I. get C.I. per min.Divide that by 1,728 to get CFM, times that by 60 to get C.F.H divide by 12.4 to get lbs per hr, take one fourteenth to get fuel Lbs per hour out of a 13:1 mixture. Divide by two to get the horse power produced by the fuel going in.

Naaah cant be right!

[Petrol Head]

I wanted to work backwards to see if the claims for what could theoretically be got out of a 750cfm on a 454 in terms of HP could be even be considered realistic.

So I thought Id take the volumetric through put split the fuel out of the mix and get the weight.

Times by two and laugh!

Thanks for the corrections.

[Petrol Head]

100% efficiency =488HP?

[Petrol Head]

Thanks for that! But thats not it.

I was looking for the HP ceiling limit based on the fuel input to a certain sized engine.

Calorifically, with 100% efficiency, you can't pull extra HP out of a hat.

So I split out the fuel and got the numbers although they are still lower than I posted.

Just been on Hot rod and I cant see their claims being realistic.

[Petrol Head]

I think this is right.:banana: ,but I thought that last time.

RPM/2 * C.I =C.I.M.
CIM/1728 =C.F.M.
get 1/14th of mixture (13:1 ratio).
convert 1/14th C.F.M. to lb per min
convert to lbs per hour
Times 2 for HP per hour

Freelance anorak... with no honour

[Petrol Head]

I 'll take it off tomorow!:hugegrin:

[Petrol Head]

And the reagtta stuff.

The mathypoos was not about forecasting my engines.

I didnt want to work out the real HP of a motor.

I wanted a flat reference point for what a blank motor would consume in petrol and as a result a loose idea of the HP you could expect from that fuel, in a motor that sizeat a given RPM.

No frills or gains.

Just C.I.M. of mixture into HP. not realistic at all but a yardstick to measure from.

[Petrol Head]

Originally posted by Matt
Don't worry, I have a selection of scary babies.

HUH, we have the real things ere!