Take the RPM times it by the C.I. get C.I. per min.Divide that by 1,728 to get CFM, times that by 60 to get C.F.H divide by 12.4 to get lbs per hr, take one fourteenth to get fuel Lbs per hour out of a 13:1 mixture. Divide by two to get the horse power produced by the fuel going in.
I wanted to work backwards to see if the claims for what could theoretically be got out of a 750cfm on a 454 in terms of HP could be even be considered realistic.
So I thought Id take the volumetric through put split the fuel out of the mix and get the weight.
I think this is right. ,but I thought that last time.
RPM/2 * C.I =C.I.M.
CIM/1728 =C.F.M.
get 1/14th of mixture (13:1 ratio).
convert 1/14th C.F.M. to lb per min
convert to lbs per hour
Times 2 for HP per hour
The mathypoos was not about forecasting my engines.
I didnt want to work out the real HP of a motor.
I wanted a flat reference point for what a blank motor would consume in petrol and as a result a loose idea of the HP you could expect from that fuel, in a motor that sizeat a given RPM.
No frills or gains.
Just C.I.M. of mixture into HP. not realistic at all but a yardstick to measure from.